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Could somebody help my effort at calculating inductor current for a given time, please?
The current (𝑖_𝐿) through a 100mH inductor (L) has a relationship with time (t). Determine the inductor current when the time is 0.75 seconds - i_L = 1/L∫cos(300t) dt
Inductor current (iL)when the time is 0.75 seconds
L= 100x10^-3
Cos(at)=1/a sin(300t)
1/300 sin(225)
1/300=3.333333333x10^-3
sin(225)=-0.930094878
Multiply both answers to :
-3.10031626x10^-3
Do I now need to multiply by 1/L answer? For my final result? Or am I way off with this?
The current (𝑖_𝐿) through a 100mH inductor (L) has a relationship with time (t). Determine the inductor current when the time is 0.75 seconds - i_L = 1/L∫cos(300t) dt
Inductor current (iL)when the time is 0.75 seconds
L= 100x10^-3
Cos(at)=1/a sin(300t)
1/300 sin(225)
1/300=3.333333333x10^-3
sin(225)=-0.930094878
Multiply both answers to :
-3.10031626x10^-3
Do I now need to multiply by 1/L answer? For my final result? Or am I way off with this?
Original post by Palmer17
Could somebody help my effort at calculating inductor current for a given time, please?
The current (𝑖_𝐿) through a 100mH inductor (L) has a relationship with time (t). Determine the inductor current when the time is 0.75 seconds - i_L = 1/L∫cos(300t) dt
The current (𝑖_𝐿) through a 100mH inductor (L) has a relationship with time (t). Determine the inductor current when the time is 0.75 seconds - i_L = 1/L∫cos(300t) dt
Just to check before anyone else tries to help, is that supposed to be or something else?
Original post by Palmer17
1/L = 1/0.1 = 10
10 x -3.10031626 = -0.0310031626
Is where I am upto now is this correct?
10 x -3.10031626 = -0.0310031626
Is where I am upto now is this correct?
That's not right, is it? Have you missed off the power of 10 ?
Original post by davros
That's not right, is it? Have you missed off the power of 10 ?
Which power of 10 and to where?
Original post by Palmer17
Which power of 10 and to where?
well 10 x -3.1 is -31 isn't it? Look back at your earlier posts - you had another multiplier in there
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