easy chem question help
R.A.M Anhydrous = 196.
R.A.M H20 = 18.
Grams of Anhydrous = 1.735g.
H3X ~ nH20 = 210g mol -1
Moles of H3X ~ nH20 = 0.00833 mol.
How do I work out the ratio of water molecules to H3X molecules using these?
Any help would be greatly appreciated
R.A.M H20 = 18.
Grams of Anhydrous = 1.735g.
H3X ~ nH20 = 210g mol -1
Moles of H3X ~ nH20 = 0.00833 mol.
How do I work out the ratio of water molecules to H3X molecules using these?
Any help would be greatly appreciated
Original post by NoRegrets :)
R.A.M Anhydrous = 196.
R.A.M H20 = 18.
Grams of Anhydrous = 1.735g.
H3X ~ nH20 = 210g mol -1
Moles of H3X ~ nH20 = 0.00833 mol.
How do I work out the ratio of water molecules to H3X molecules using these?
Any help would be greatly appreciated
R.A.M H20 = 18.
Grams of Anhydrous = 1.735g.
H3X ~ nH20 = 210g mol -1
Moles of H3X ~ nH20 = 0.00833 mol.
How do I work out the ratio of water molecules to H3X molecules using these?
Any help would be greatly appreciated
If you've got the Mr of the anhydrous salt and the mass you can work out the moles.
You've already got the moles of water.
Now work out the integer ratio between the two values.
why have you posted this question twice? (the other is here)
Please don't post the same question twice! It wastes people's time!
Please don't post the same question twice! It wastes people's time!
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