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statistics help

three dice are thrown. find the probability of obtaining:

(i) at least two 6s

i did 3((1/6)^2*5/6) which is wrong.. why is it wrong?

(ii) different scores on all the dice

how should i do this?

Reply 1

ghostwalker

Original post by Student#123

three dice are thrown. find the probability of obtaining:

(i) at least two 6s

i did 3((1/6)^2*5/6) which is wrong.. why is it wrong?

At least two, means two or three in this case.

(ii) different scores on all the dice

how should i do this?

First die can be anything.
Then what's the probability that the second die is different.
Then the third.

Reply 2

Student#123

Original post by ghostwalker

At least two, means two or three in this case.

First die can be anything.
Then what's the probability that the second die is different.
Then the third.

how do i work it out???

Reply 3

ghostwalker

Original post by Student#123

how do i work it out???

Once the first die has been rolled, one number has been allocated.

So, when you roll the second die, what's the probability that it is different to the first? How many choices do you have, out of how many?