The Student Room Group

Help on a part of a STEP question please.

How do you get the RHS starting with only the LHS ?
Thanks in advance!
Original post by Glavien
How do you get the RHS starting with only the LHS ?
Thanks in advance!


Add something to the numerator and take the same thing away. Think for a bit about what you should add and take away. If you can't think of it, starting from the RHS should give you the idea.
Original post by Glavien
How do you get the RHS starting with only the LHS ?
Thanks in advance!


How can the LHS be equal to RHS ? I would also really want to know how people approach this question :colone:
Reply 3
Original post by morgan8002
Add something to the numerator and take the same thing away. Think for a bit about what you should add and take away. If you can't think of it, starting from the RHS should give you the idea.


I'm sorry I'm really confused, what do you add something then take it away?


Posted from TSR Mobile
Original post by Glavien
I'm sorry I'm really confused, what do you add something then take it away?


Posted from TSR Mobile


If you don't see it then start from the RHS and try to get the LHS. Reverse the process to go from the LHS to the RHS.
Reply 5
I'd say long division?
Reply 6
Original post by H.A.
I'd say long division?

Yes, that works thank you!!



Posted from TSR Mobile
Reply 7
Original post by Glavien
Yes, that works thank you!!



Posted from TSR Mobile


Just by the way, this thread exists: http://www.thestudentroom.co.uk/showthread.php?t=3478331
Reply 8
Original post by Glavien
How do you get the RHS starting with only the LHS ?
Thanks in advance!


Now that you've already done it, the method that Morgan was referring to is:

x31+x2x3+xx1+x2x3+x1+x2x1+x2xx1+x2\displaystyle \frac{x^3}{1+x^2} \equiv \frac{x^3 +x - x}{1+x^2}\equiv \frac{x^3 +x}{1+x^2} - \frac{x}{1+x^2} \equiv x - \frac{x}{1+x^2}

Which is much cleaner and nicer than long division, in my opinion.
Reply 9
^agreed.

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