C2 Maths question
I got this question:
log 3 (9x) + log 3 (x^5 /81) = 3
What i did is get:
log 3 (9x X x^5 /81) = 3
Meaning that (9x X x^5 /81) = 1
This means that:
9x^6/81 = 1
I then solved x as 1.4422495
Is this a wrong method?
Thanks in advance
log 3 (9x) + log 3 (x^5 /81) = 3
What i did is get:
log 3 (9x X x^5 /81) = 3
Meaning that (9x X x^5 /81) = 1
This means that:
9x^6/81 = 1
I then solved x as 1.4422495
Is this a wrong method?
Thanks in advance
means that , check your 5th line.
When you get log 3 (9x X x^5 /81) = 3 ===> you should get log 3 (9x^6 /81) = 3 ===> this leaves with 3^3 = 9x^6 /81 ===> 27 = 9x^6 /81 ===> 2187 = 9x^6 ===> x^6 = 243 therefore x = 2.498 (3dp)
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