Does anyone have the answers for this gcse grade 9 paper??

http://m4ths.com/grade-9-gcse.html
I just did paper 2 and I'm curious to find out how I did. Does anyone have the answers??


Posted from TSR Mobile

You have to buy them... the questions are free though

:/ does any maths genius mind doing the paper then??


Posted from TSR Mobile

I might have a go later... I'll share the answers and we can compare if that helps!

Okay thanks


Posted from TSR Mobile

What answers did you get for the first few questions?

What answers did you get for the first few questions?

May as well share them all
1) 125
2) I don't know how to do it
3)I think I got this. Turning point (-4,-3) passes through (-9,0) and (0,1)
4) I showed that the line intersects the circle at two points (-5.3,-2.98) and (4.7,2.7) and also that it passes through the origin by rearranging the equation and showing that when x is 0 y is also 0.
5)5.5 metres, 1.5 seconds
6)135 units
7)18 minutes
8) SAS. AB=BC, angle BAX= angle BCY (because the triangle was isosceles), AX=YC (because they are both 1/4 of AC)
9)y=(5-2x^3)/x^2
10)I don't know how to do this :/
11)x=p, y=q so y+(x/2) is q+(p/2)=B
12)x=112.5 degrees and x=300 degrees. Unsure about this
13) a) x=p, y=q or x=r, y=s
b) I don't know
14)Michael was in the top 25% of performers in class X
15)2
16)35.4 cm^2
17)28.563 degrees


Posted from TSR Mobile

I got 2/(20x+27) for the second question. Not sure what I did wrong since it says a and b are integers.

which sections did you include? I got B (intersect) C (not including) A. But what does the line C mean at the end?

I did this a long time ago so I think I am remembering it right.

The line means probability of B (intersect) A' given C.

The line means "given that" - it is conditional probability.

When that line is there, you follow this general formula:

P(X|Y) = P(X(intersect)Y) / P(Y)
so in our case it is:

X = B(intersect) A'
Y = C

so it is P(B (intersect) A' (intersect) C) / P(C)

I did this a long time ago so I think I am remembering it right.

The line means probability of B (intersect) A' given C.

The line means "given that" - it is conditional probability.

When that line is there, you follow this general formula:

P(X|Y) = P(X(intersect)Y) / P(Y)
so in our case it is:

X = B(intersect) A'
Y = C

so it is P(B (intersect) A' (intersect) C) / P(C)

Thanks for explaining that do you think we will be questioned on the line in an exam?


Posted from TSR Mobile

"Additionally" should be replaced by "alternatively" because showing that the line passes through the centre is enough to prove it contains the diameter of the circle.

Find the centre coordinates of the circle, run them through the line, if the eq. of the line is satisfied, the line and circle's centre coincide. Job done. I don't see the need for substitutions and such.

What exam board are you doing? AQA just needs you to know the phrase 'what is the probability of x given y' which they'll just give in the question.

Thanks for explaining that do you think we will be questioned on the line in an exam?


Posted from TSR Mobile

What exam board are you doing? AQA just needs you to know the phrase 'what is the probability of x given y' which they'll just give in the question.

I'm doing AQA. I can do questions with that phrase so I'm okay What exam board are you doing?


Posted from TSR Mobile

For question number 4, here's how I proved it:

x²+y² = 25 (1.0)
3x+4y = 0 (2.0)

rearrange equation (2.0) to give y = -3x/4.

substitute into (1.0) to get x = +4 and x = -4
subsitute these values back into equation (2.0) to get y = +3 and y = -3

So when x = 4 y = -3 and when x = -4, y = 3
4²+(-3)²= 25
and similarly
(-4)²+3²= 25.

Therefore, a part of the line 3x+4y = 0 must be the diameter as it intersects the circle at those two points and fits the equation of the circle. Additionally, you can prove that the line passes through the origin.