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YasminBedford
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#1
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1. Which one of these statements concerning methyl 2-methylpropenoate is not true?

a) it displays geometrical isomerism
b) it forms an addition polymer
c) it undergoes reduction
d) it decolourises bromine
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ChemistryWebsite
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Which have you eliminated so far?
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YasminBedford
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(Original post by TutorsChemistry)
Which have you eliminated so far?
I have eliminated A and B
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ChemistryWebsite
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(Original post by YasminBedford)
I have eliminated A and B
Good.
As per the other thread you have posted, what does the bromine water test tell you? Would this compund give a positive response (decolourisation) or not?
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YasminBedford
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(Original post by YasminBedford)
I have eliminated A and B
Is the false answer C?
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Guarddyyy
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If you remember that bromine is orange, and when an alkene (double bond) is present, it will decolourise and the bromine will be substituted into the double bonds.

Does the compound have a double bond?

TutorsChemistry I hope I'm right as well Gotta get my revision done XD
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ChemistryWebsite
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(Original post by YasminBedford)
Is the false answer C?
It is an organic acid anion so would undergo reduction.
(Original post by Guarddyyy)
If you remember that bromine is orange, and when an alkene (double bond) is present, it will decolourise and the bromine will be substituted into the double bonds.

Does the compound have a double bond?

TutorsChemistry I hope I'm right as well Gotta get my revision done XD
It does have a double bond, so would decolurise bromine.




Let's have a closer look at A. Did anyone draw out the structure?
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Pigster
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(Original post by TutorsChemistry)
Did anyone draw out the structure?
I did. Do I get a sticker?
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ChemistryWebsite
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(Original post by Pigster)
I did. Do I get a sticker?
Top of the class.

Hopefully you also concluded the compound can't display geometric isomerism?
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YasminBedford
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I'm so confused which answer from a-d is false???
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ChemistryWebsite
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(Original post by YasminBedford)
I'm so confused which answer from a-d is false???
I make it A.
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charco
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CH2=CH(CH3)COOCH3

can't have geometric isomers as there are two groups (H-atoms) the same on one carbon of the double bond ...
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