Functions (As Maths)

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$f(2) = 0$ means if you substitute in $x=2$ into $f(x)$ then equate it to zero, you end up with an equation in two variables $b,c$.

Now, if you use similar information regarding division by $(x+3)$, you end up with another equation in $b,c$.

Hence, you would end up solving a pair of simultaneous equations for $b,c$.

So the question is this ... are you familiar with the Remainder Theorem?

is this correct so far? I think i remember the remainder theorem

$16+2b+c = 0$ is correct.

I am not sure why you are trying to divide this expression by x+3 though. Just leave it alone.

Well, look through your notes or textbook. What does the remainder theorem say ?

$16+2b+c = 0$ is correct.

I am not sure why you are trying to divide this expression by x+3 though. Just leave it alone.

Well, look through your notes or textbook. What does the remainder theorem say ?

Let factor = a
If f(x)/(x+3) = a and remainder 85
f(x) = a(x+3) + 85

Let x = -3...

I'm sorry but I'm really confused

I'm sorry but I'm really confused