Urgently need some probability (addition rule) help
The addition rule is easy to do when its P(AUB) but Im having immense difficulty when its P(A'UB) or P(AUB'). I have the solution bank and have looked the Venn diagrams, I see which numbers they use but I cant seem to understand why.
Can somebody please help because Ive been stuck on it for a day now!
Can somebody please help because Ive been stuck on it for a day now!
Goodness wasted so much time.
P(A'UB) would open up as
P(A') + P(B) - P(A'nB)
To get P(A'), simply '1 - P(A)' and P(A'nB) is easily read off from the Venn diagram.
P(A'UB) would open up as
P(A') + P(B) - P(A'nB)
To get P(A'), simply '1 - P(A)' and P(A'nB) is easily read off from the Venn diagram.
Original post by FirstDiscovery
Goodness wasted so much time.
P(A'UB) would open up as
P(A') + P(B) - P(A'nB)
To get P(A'), simply '1 - P(A)' and P(A'nB) is easily read off from the Venn diagram.
P(A'UB) would open up as
P(A') + P(B) - P(A'nB)
To get P(A'), simply '1 - P(A)' and P(A'nB) is easily read off from the Venn diagram.
Yes, ok. But what about it don't you understand?
Do you understand why
Or why P(A^c \cap B) = P(A^c) + P(B) - P(A^c \cap B) ?
Original post by ekudamram
Yes, ok. But what about it don't you understand?
Do you understand why
Or why P(A^c \cap B) = P(A^c) + P(B) - P(A^c \cap B)
Do you understand why
Or why P(A^c \cap B) = P(A^c) + P(B) - P(A^c \cap B)
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