C4 Question Help
x= sint + t, y= sint,
a) find dy/dx in terms of t.b) Find, in exact form, the coordinates of the point where thetangent to the curve is parallel to the x-axisc) Show thatthe region bounded by the curve and the x-axis has area 2.
I have done part a) and got the answer of cost/(1+cost) which I know is correct. I don't know how you do part b) and c) as there are no co-ordinates give. The curves touches the x-axis at 0 and another unlabelled point.
a) find dy/dx in terms of t.b) Find, in exact form, the coordinates of the point where thetangent to the curve is parallel to the x-axisc) Show thatthe region bounded by the curve and the x-axis has area 2.
I have done part a) and got the answer of cost/(1+cost) which I know is correct. I don't know how you do part b) and c) as there are no co-ordinates give. The curves touches the x-axis at 0 and another unlabelled point.
(edited 8 years ago)
@Improvement, please edit your OP 
Original post by Kvothe the arcane
@Improvement, please edit your OP
Just done it.
Original post by Improvement
x= sint + t, y= sint,
a) find dy/dx in terms of t.
a) find dy/dx in terms of t.
I have done part a) and got the answer of cost/(1+cost) which I know is correct. I don't know how you do part b) and c) as there are no co-ordinates give. The curves touches the x-axis at 0 and another unlabelled point.
The tangent to the curve is parallel to the x axis when there is no gain in y, ie when dy/dx=0.
Original post by Kvothe the arcane
The tangent to the curve is parallel to the x axis when there is no gain in y, ie when dy/dx=0.
so it will be the TP co-ordinate of the curve? so I would make cos(t)/1+cost = 0?
so cos(t) =0?
Got the answer to b) only need to do c now
Original post by Improvement
so it will be the TP co-ordinate of the curve? so I would make cos(t)/1+cost = 0?
so cos(t) =0?
so cos(t) =0?
Indeed
Original post by Improvement
Got the answer to b) only need to do c now
Was there an image of the graph or a range?
Original post by Kvothe the arcane
Was there an image of the graph or a range?
It is in the positive quadrant of the graph and comes from the origin to an unmarked point of the x-axis where it ends.
Original post by Improvement
It is in the positive quadrant of the graph and comes from the origin to an unmarked point of the x-axis where it ends.
Any chance you can upload an image?
Original post by Kvothe the arcane
Any chance you can upload an image?
Posted from TSR Mobile
Original post by Kvothe the arcane
So the limits are 0 and pi (I might be wrong).
I have y obviously as sint and dx/dt = 1+cost so before integrating should I multiple the brackets? or just keep them as they are?
Original post by Improvement
I have y obviously as sint and dx/dt = 1+cost so before integrating should I multiple the brackets? or just keep them as they are?
I have y obviously as sint and dx/dt = 1+cost so before integrating should I multiple the brackets? or just keep them as they are?
Well you do what you think you need to do to integrate.
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Original post by Kvothe the arcane
Well you do what you think you need to do to integrate.
Sent from my SM-G925F using Tapatalk
Sent from my SM-G925F using Tapatalk
I got the answer
thanks guys!No worries @Improvement, I'm glad we were able to help.
Original post by Kvothe the arcane
No worries @Improvement, I'm glad we were able to help.
you called my Lord?
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