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The line joining (-3,-2) to(2e,5) has the gradient 2.Work out the value of e.

Reply 1

student004

Original post by iqra26

Could someone help with this question Thanks:

The line joining (-3,-2) to(2e,5) has the gradient 2.Work out the value of e.

use the equation
(y-y1)=m(x-x1)
y+2=2(x+3)
y=2x+8

substitute:
5=2(2e)+8
-3=4e
e= -3/4

Reply 2

IfYouCanDreamIt

I'm not sure if this is right, but I'm sure someone will correct me if it's not. But I subbed the values into the formula to find the gradient (difference in y)/(difference in x)

So I had (5--2)/(2e--3)=2 which I then simplified down to 7/2e+3=2. I then multiplied both sides by (2e+3) and then worked it out from there.
So 7=4e+6
1=4e
e=1/4

(edited 7 years ago)

Reply 3

IfYouCanDreamIt

Original post by student004

use the equation
(y-y1)=m(x-x1)
y+2=2(x+3)
y=2x+8

substitute:
5=2(2e)+8
-3=4e
e= -3/4

Sorry I don't want to step on your toes but I think when you had y+2=2(x+3) you added 2 to both sides rather than subtracting. So it should be y=2x+4
so 5=2(2e)+4
1=4e
e=1/4

Sorry if you were right and I misread your working