AS Maths - changing the subject of an equation

Im not sure if this is correct but this is what i didexpand = (2x 2e)/ftimes the denominator = f(x c) = d(2x 2e)expand again = fx fc = 2dx 2deminus fc fx= 2dx 2de-fcdivide by f x= (2dx 2de-fc)/fI don't do maths but i do chem and bio AS sorry if its wrongGood luck x

Thanks for trying to help - I've got the answer in a booklet but it's different to yours (I had just needed to understand how to work it out) but you definitely gave it a good go for not doing AS maths Thank you anyway!

Have you tried working it out? Where did you get stuck?

I have but I'm not sure whether to expand the brackets on the right hand side, or what values I should move to what side etc. I'm just confused about how to do this question as a whole :/

I have but I'm not sure whether to expand the brackets on the right hand side, or what values I should move to what side etc. I'm just confused about how to do this question as a whole :/

I would multiply through to eliminate the fractions then exapnd the brackets. You then need to collect the terms in x.

Post your working if you get stuck.

I tried to work it out by moving the d denominator of the first fraction to the right side 'd(2x+2e)' and moved the f denominator to the left side to make 'f(x+c)' then expanded the brackets to make fx+c = 2dx+2e. I then moved the c over to make 2dx+2e -c and finally moved the f and got x = 2dx+2e-c/f but in the answer booklet it says the answer is 'x = 2de-fc/f-2d' - what did I do wrong?

I tried to work it out by moving the d denominator of the first fraction to the right side 'd(2x+2e)' and moved the f denominator to the left side to make 'f(x+c)' then expanded the brackets to make fx+c = 2dx+2e. I then moved the c over to make 2dx+2e -c and finally moved the f and got x = 2dx+2e-c/f but in the answer booklet it says the answer is 'x = 2de-fc/f-2d' - what did I do wrong?

I tried to work it out by moving the d denominator of the first fraction to the right side 'd(2x+2e)' and moved the f denominator to the left side to make 'f(x+c)' then expanded the brackets to make fx+c = 2dx+2e. I then moved the c over to make 2dx+2e -c and finally moved the f and got x = 2dx+2e-c/f but in the answer booklet it says the answer is 'x = 2de-fc/f-2d' - what did I do wrong?

Check expansion of brackets ..

OK - note that x appears on both sides of your equation:
fx + fc = 2dx + 2de

Collect them on the LHS
fx - 2dx = 2de -fc

Can you see what to do now?

Your first step is correct but when you expand brackets, you have to multiply all the terms in the brackets by the term(s) outside it. So you should have $fx + fc = 2xd + 2ed$. Can you continue from there?

I understand now, thank you!