[br]\dfrac{d}{dt}|\dfrac{dP}{dt}|=0 \\[br]\dfrac{1}{T} \int_0^T Re(P(t))dt = \dfrac{\sqrt{40}-5}{6} \\[br]\dfrac{1}{T} \int_0^T t Im(P(t))dt = \dfrac{\sqrt{5}-\sqrt{8}}{6}[br]
[br]\dfrac{d}{dt}|\dfrac{dP}{dt}|=0 \\[br]
[br]x=\dfrac{\sqrt{10}-5}{6}\\[br]y=\dfrac{\sqrt{5}-\sqrt{8}}{6t}[br]
[br]x=\dfrac{\sqrt{10}-5}{6}\\[br]y=\dfrac{\sqrt{5}-\sqrt{8}}{6t}[br]
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