Original post by Rianne.-.
How is this work? As final variable n is 13.
n <— 2
t <— n LEFTSHIFT 3
t <— t- 1
n <— t- n
n <— 2
t <— n LEFTSHIFT 3
t <— t- 1
n <— t- n
The LEFTSHIFT operation takes the left operand (in your case, n) and multiplies it by 2^x, where x is the right operand.
Thus in your case, n would be multiplied by 2^3, the right operand:
2^3 = 8, and 2 * 8 = 16
Moving to the next line:
t <— t- 1
Subtracting 1 from 16 gives us 15.
Finally, 15 - n = 15 - 2 = 13.
(edited 11 months ago)
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