Chem a level

Page 4 of 12
What evidence from the diagram supports the fact that no more than three unpaired electrons can be accommodated in the 3p sub-lever?

Can’t upload graph unfortunately but if you know this question please help and explain

if you could take a picture of it or a sc and then press this button here you will acc be able to upload the question. if not you could always try to find a link to it online and I can have a look if I know it.

good luck x

Ah thank you!

Because the graph dips from the 3p3 to 3p4 and that is because now a electron with the opposite spin is joining the orbital and therefore there is a slight repultion because of it so the ionisation energy drops because of it. Hope this makes sence <3, if not I can always tag others who might know better than me

Thank u I definitely do understand better. Can you please explain the mark scheme answer I wrote on the page.
Just the part of
“The idea block of 3 elements”

Thank u I definitely do understand better. Can you please explain the mark scheme answer I wrote on the page.
Just the part of
“The idea block of 3 elements”

I can't actually see where you wrote “The idea block of 3 elements”.

But, I suppose you need the answer for part (iv).

There is a drop in ionisation energy from phosphorus to sulfur, indicating that the outer electron in sulfur is higher in energy than that of phosphorus. This is counter to the fact that the nuclear attraction has increased from phosphorus to sulfur, therefore there is another factor to be taken into account and that is the increased inter-electron repulsion of a pair of electrons in the same 'p' orbital.

So, the evidence is the lower than expected 1st ionisation energy of sulfur.