C4 Integration Maths Question: Where did I go wrong..?
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Original post by creativebuzz
I've attached my working out! 
sin2x = 2sinxcosx
very first line
Original post by TeeEm
sin2x = 2sinxcosx
very first line
very first line
Ah thank you!
Could you spot where I went wrong in this question:
Original post by tiddlytom
You've calculated the integral of cos(x)^2sin(x)^2 not 1/that.
Ah thank you!
Could you spot where I went wrong in this question?
Original post by creativebuzz
Ah thank you!
Could you spot where I went wrong in this question:
Could you spot where I went wrong in this question:
i do not see anything wrong
Original post by TeeEm
i do not see anything wrong
Oh okay, because when I tried plugging
1/tan(7 x pi/2) into my calculator I kept getting an error..
Am I plugging it into the calculator wrong or?
Original post by creativebuzz
Oh okay, because when I tried plugging
1/tan(7 x pi/2) into my calculator I kept getting an error..
Am I plugging it into the calculator wrong or?
1/tan(7 x pi/2) into my calculator I kept getting an error..
Am I plugging it into the calculator wrong or?
I suspect your calculator is not good enough to handle it.
Original post by TeeEm
I suspect your calculator is not good enough to handle it.
..so what should I do? :/
Original post by creativebuzz
..so what should I do? :/
do you know what is the tan(pi/2)?
Original post by creativebuzz
Ah thank you!
Could you spot where I went wrong in this question?
Could you spot where I went wrong in this question?
When you evaluate the bottom limit, you get 2.275. I think it should be 1.23.
Ideally, give your answer exactly as well as a decimal.
Original post by tiddlytom
When you evaluate the bottom limit, you get 2.275. I think it should be 1.23.
Ideally, give your answer exactly as well as a decimal.
Ideally, give your answer exactly as well as a decimal.
Ah got it! Thank you!
Do you know where I could go with this question?
Original post by TeeEm
do you know what is the tan(pi/2)?
Isn't there an asymptote there? Hence, the error
Original post by creativebuzz
Isn't there an asymptote there? Hence, the error
asymptote: yes
error: no
Original post by TeeEm
asymptote: yes
error: no
error: no
So how come I get an error every time I attempt it in my calculator?
Original post by creativebuzz
So how come I get an error every time I attempt it in my calculator?
It is because your calculator is made in Japan...
mine gives an answer ...
Original post by creativebuzz
A
Ah got it! Thank you!
Do you know where I could go with this question?
Ah got it! Thank you!
Do you know where I could go with this question?
The integral of -4/(2x+1) is done in the same way as the other term. (the top is a constant factor times the derivative of the bottom)
Original post by creativebuzz
A
Ah got it! Thank you!
Do you know where I could go with this question?
Ah got it! Thank you!
Do you know where I could go with this question?
fixed
Original post by tiddlytom
The integral of -4/(2x+1) is done in the same way as the other term. (the top is a constant factor times the derivative of the bottom)
Ah okay! By the way, have you done FP1/Further Maths?
Original post by creativebuzz
Ah okay! By the way, have you done FP1/Further Maths?
Yeah, did further maths a few years ago - doesn't guarantee I remember it all!
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