Don't we need to divide it by 1000? Also isnt change in minus?
Divide the Delta h by 1000- you can but its easier to do at end of calculation- delta h=-q/n but its easier to use q/ n and convert at the end depending on whether the reaction is exothermic or endothermic- this one is exo so it is negative so answer is 2508/0.05=50160j/mol, you can divide by 1000 to get 50.16kj/mol and put a negative as its exo for final answer of -50.16kj/mol
Divide the Delta h by 1000- you can but its easier to do at end of calculation- delta h=-q/n but its easier to use q/ n and convert at the end depending on whether the reaction is exothermic or endothermic- this one is exo so it is negative so answer is 2508/0.05=50160j/mol, you can divide by 1000 to get 50.16kj/mol and put a negative as its exo for final answer of -50.16kj/mol
I thought like you divide the 2508j by 1000? Or is it already converted? So how do you if it's exo or endo and so question will be 100x4.18x18.8??
I thought like you divide the 2508j by 1000? Or is it already converted? So how do you if it's exo or endo and so question will be 100x4.18x18.8??
you can divide it by 1000- do that if youre comfortable- i suggested doing that at the end but whatever youre used to and im looking at q1 where the temp change is 12 and mass=50, exo and endo is deduced from whether temp has risen or fallen- if surroundings risen, exothermic - if surrounding temp fallen, endothermic
you can divide it by 1000- do that if youre comfortable- i suggested doing that at the end but whatever youre used to and im looking at q1 where the temp change is 12 and mass=50, exo and endo is deduced from whether temp has risen or fallen- if surroundings risen, exothermic - if surrounding temp fallen, endothermic