Organic chemistry - alkanes

What would you draw 3,3,3, tri methylheptane ?
thanks

3,3,3-trimethylheptane can't exist- are you sure it's the correct name?

To OP: try drawing it (with hydrogens if you need to), and figure out why it can't exist...

3,3,3-trimethylheptane can't exist- are you sure it's the correct name?

For 4,4,5-triethyl-5-propylnonane, draw a carbon chain 9 carbons long- from the nonane part.
Then number the carbons (in this case, it doesn't matter which side you number from, but in other cases the highest priority functional group would decide which side to start from)
Then draw the ethyl and propyl groups at the correct carbons

Oh no there was a structural formula and you had to name it

Are you able to name those two structures?

I know the first one but not the second for the second one I got 3ethyl 4metyl heptane

I know the first one but not the second for the second one I got 3ethyl 4metyl heptane

That's correct for the second one

That's what I would have thought!

That's correct for the second one

This one was the one I was stuck on

First of all you need to identify the longest carbon chain, if there's two of the same length, the correct one is that in which the highest priority group has the lowest number.
Once you've done that, then just number the chain as usual and identify the groups attached onto the carbons
Have you had a go at this one?

Yeh i did but it doesn't exist haha
Do you have to number as usual ? My teacher didn't tell me to do that though

What did she say?
You have to number as usual, but only after identifying the correct carbon chain. I admit I'm having difficulty with this as I'm not entirely sure which is higher priority!
What's the longest chain of carbons in this?

http://www.chem.uiuc.edu/GenChemReferences/nomenclature_rules.html

Have a read; rule number 6 will be useful for this!